In Shuttle Sort technique for n elements in an array a, it requires n-1 passes. When i-th pass(1<=i<=n) begins, the first i elements, i.e., elements a[0] to a[i-1] have been sorted and these occupy the first i positions of the array. To insert (i+1)th element, a[i] is compared with a[i-1] and if the value of a[i] is smaller than a[i-1] then they are exchanged. In the same way the process continues until either no exchange is required or the beginning of the array is reached.

Time complexity of the algorithm is O(n^2).

The complete source code is given below

 * File:   ShuttleSort.c
 * Author:

#include <stdio.h>
#include <stdlib.h>

void shuttleSort(int a[], int n) {
    int i = 1, j;
    int temp;
    while (i < n) {
        j = i - 1;
        while (j >= 0) {
            if (a[j] > a[j + 1]) {
                temp = a[j];
                a[j] = a[j + 1];
                a[j + 1] = temp;
            } else {
    printf("\nThe sorted array elements are given below\n");
    for (i = 0; i < n; i++) {
        printf("a[%d]=%d ", i, a[i]);

int main() {
    int i, n = 6;
    int a[] = {15, 8, 17, 12, 38, 19};
    printf("\n:: Shuttle Sort ::\n");
    printf("\nInput array elements\n");
    for (i = 0; i < n; i++) {
        printf("a[%d]=%d ", i, a[i]);
    shuttleSort(a, n);


:: Shuttle Sort ::

Input array elements
a[0]=15 a[1]=8 a[2]=17 a[3]=12 a[4]=38 a[5]=19 

The sorted array elements are given below
a[0]=8 a[1]=12 a[2]=15 a[3]=17 a[4]=19 a[5]=38

Thanks for reading.

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